with t as(
select '11:00' time1, '2' value1,'3' value2 from dual
union all
select '11:30' time1, '4' value1,'5' value2 from dual
union all
select '11:00' time1, '3' value1,'3' value2 from dual
union all
select '11:30' time1, '4' value1,'3' value2 from dual

)
select tt.time1,tt.value1,tt.value2
from (
select t.time1,t.value1,t.value2,row_number() over(partition by t.time1 order by t.value1) rn
from t) tt
where tt.rn = 1

------解决方案--------------------
借用滤重的语句也可以

SQL code
select * from 
   from table
  where rowid in
     ( select max(rowid) from table
             group by time)

------解决方案--------------------
select * from temp where rowid in (select max(rowid) from temp group by time)

------解决方案--------------------

为啥上面都写的这么麻烦呢？  这样可以么
SQL code

select time ,
       max(vale1), 
       max(value2)
from A
group by time

------解决方案--------------------
用row_number()(partition by 字段 order by 字段 ) 是比较好的方法！

------解决方案--------------------
select time ,min(vale1) ,max(vale2) from table group by time

------解决方案--------------------
+1      天朝的人都喜欢拿简单的事复杂化。
探讨

为啥上面都写的这么麻烦呢？ 这样可以么

SQL code
select time ,
       max(vale1), 
       max(value2)
from A
group by time