日期:2014-05-17  浏览次数:20756 次

这条sql怎么改?
SELECT NAME, (DECODE (kpi_id, '210504', kpi_value, '0')) 铁塔角度x,
  (DECODE (kpi_id, '210505', kpi_value, '0')) 铁塔角度y, (DECODE (kpi_id, '210501', kpi_value, '0')) 温度
  FROM (SELECT his.kpi_value,
  TO_CHAR (his.cll_time, 'MM-DD HH24:MI:SS') AS NAME,
  his.kpi_id
  FROM table1 his where his.kpi_id IN ('210505', '210504','210501'))

这样一条sql

得出的结果是 同一时间多条记录  

 NAME 铁塔角度x 铁塔角度y 温度
  
 09-01 00:01:32 1 0 0  
 09-01 00:01:32 0 1 0  
 09-01 00:01:32 0 0 1  
 09-01 00:02:32 2 0 0  
  09-01 00:02:32 0 0 2  
   
要求是 把多条数据在同时间合并  

 NAME 铁塔角度x 铁塔角度y 温度  
  09-01 00:01:32 1 1 1  
  09-01 00:02:32 2 0 2  
   
  各个帮忙看看sql怎么写

------解决方案--------------------
SQL code

--这个应该可以,你整的也太麻烦了
select
    TO_CHAR (his.cll_time, 'MM-DD HH24:MI:SS') AS NAME,
    max(DECODE (kpi_id, '210504', kpi_value, '0')) 铁塔角度x,
    max(DECODE (kpi_id, '210505', kpi_value, '0')) 铁塔角度y,
    max(DECODE (kpi_id, '210501', kpi_value, '0')) 温度
from table1 his
where his.kpi_id IN ('210505', '210504','210501')
group by TO_CHAR (his.cll_time, 'MM-DD HH24:MI:SS');