日期:2014-05-17  浏览次数:21083 次

求一个三个表连接的SQL,多谢了!
表的结构和要求如下:
表名:Studentinfo:
studentid name sex
001 张三 男
002 赵四 女
表名:Coursescore
Studentid maths english
001 80 90
002 75 95
表名:Teacherinfo
teacherid tname course
101 美女 maths
102 帅哥 english

想要的结果:请各位指导SQL如何写:
Studentid name sex course score tname
001 张三 男 maths 80 美女
001 张三 男 english 90 帅哥
002 赵四 女 maths 75 美女
002 赵四 女 english 95 帅哥


------解决方案--------------------
SQL code
select m.*,n.course , o.maths score n.tname
from Studentinfo m ,  Teacherinfo n , Coursescore o 
where m.studentid = n.studentid and m.studentid = o.studentid 
union all
select m.*,n.course , o.english score n.tname
from Studentinfo m ,  Teacherinfo n , Coursescore o 
where m.studentid = n.studentid and m.studentid = o.studentid

------解决方案--------------------
SELECT A.*,c.course,b.maths,c.tname
FROM studentinfo A,coursescore b,teacherinfo c
where a.studentid=b.studentid and c.course='maths'
UNION ALL
SELECT A.*,c.course,b.english,c.tname
FROM studentinfo A,coursescore b,teacherinfo c
where a.studentid=b.studentid and c.course='english'

这个Coursescore表结构设计得不合理..
------解决方案--------------------
SQL code
create table Studentinfo(studentid varchar(10),name varchar(10),sex varchar(10))
insert into Studentinfo values('001', '张三', '男')
insert into Studentinfo values('002', '赵四', '女')
create table Coursescore(Studentid varchar(10),maths int,english int)
insert into Coursescore values('001', 80 ,90)
insert into Coursescore values('002', 75 ,95)
create table Teacherinfo(teacherid varchar(10),tname varchar(10),course varchar(10))
insert into Teacherinfo values('101', '美女', 'maths')
insert into Teacherinfo values('102', '帅哥', 'english')
go

select m.*,n.course , o.maths score ,n.tname
from Studentinfo m ,  Teacherinfo n , Coursescore o 
where m.studentid = o.studentid and n.course = 'maths'
union all
select m.*,n.course , o.english score ,n.tname
from Studentinfo m ,  Teacherinfo n , Coursescore o 
where m.studentid = o.studentid and n.course = 'english'


drop table Studentinfo , Coursescore ,Teacherinfo

/*
studentid  name       sex        course     score       tname      
---------- ---------- ---------- ---------- ----------- ---------- 
001        张三         男          maths      80          美女
002        赵四         女          maths      75          美女
001        张三         男          english    90          帅哥
002        赵四         女          english    95          帅哥

(所影响的行数为 4 行)

*/

------解决方案--------------------
SQL code
with Studentinfo as(
  select '001' studentid,'张三' name,'男' sex from dual union                 
  select '002' studentid,'赵四' name,'女' sex from dual),
Coursescore as(                 
  select '001' studentid, 80 maths, 90 english from dual union
  select '002' studentid, 75 maths, 95 english from dual),                 
Teacherinfo as(
  select '101' teacherid,'美女' tname, 'maths'   course from dual union                 
  select '102' teacherid,'帅哥' tname, 'english' course from dual)

SELECT s.Studentid, s.name, s.sex, c.course, c.score, t.tname
  FROM Studentinfo s,
       (SELECT studentid, 'maths' course, maths score
          FROM Coursescore
        UNION ALL
        SELECT studentid, 'english' course, english score FROM Coursescore) c,
       Teacherinfo t
 WHERE s.studentid = c.studentid AND
       c.course = t.course;

------解决方案--------------------
用哥这个笛卡尔积的:
SQL code

SQL> select s.studentid, s.name, s.sex, t.course,
  2         (select case when t.course = 'maths'     then maths
  3                      when t.course = 'english'   then english
  4