日期:2014-05-18 浏览次数:20574 次
--SQL2005環境: ;with NewYear as (select 1 as ID union all select ID+1 as ID from NewYear where ID<888--以888為例 ),NewYear168 as (select *,(ID-1)/88 as ID2 from NewYear where (ID/8)=ID*1.0/8 ),NewYear2010 as ( select top 88 t2.ID as [Floor], rtrim((t2.ID-1)%188+1) as Qty --188可為吉祥數字 from (select distinct ID2 from NewYear168)t cross apply (select top 10 * from NewYear168 where ID2=t.ID2 order by NewID())t2 order by newID()) select [Floor]as 樓層, cast(stuff(replace([Qty],'4','8'),len([Qty]),1,'8') as int) as 中獎紅包 from NewYear2010 order by 1 option(MAXRECURSION 0) --把結尾數改為8,把中間有其它數字有4的改為8。
樓層 中獎紅包 8 8 24 28 32 38 40 88 64 68 88 88 96 98 104 108 112 118 120 128 128 128 136 138 152 158 160 168 168 168 176 178 184 188 192 8 208 28 216 28 232 88 240 58 248 68 256 68 264 78 272 88 288 108 296 108 312 128 336 188 344 158 368 188 376 188 384 8 392 18 400 28 408 38 416 88 424 88 432 58 440 68 448 78 456 88 464 88 480 108 488 118 496 128 504 128 512 138 520 188 528 158 536 168 544 168 552 178 560 188 568 8 576 18 600 38 608 88 616 58 624 68 632 68 648 88 656 98 664 108 672 108 680 118 688 128 696 138 704 188 720 158 728 168 736 178 744 188 752 188 760 8 776 28 784 38 792 88 808 58 816 68 824 78 832 88 848 98 856 108 864 118 880 128 888 138
--SQL2005環境: if object_id('Tempdb..#NewYear2208') is not null drop table #NewYear2208 ;with NewYear as (select 889 as ID union all select ID+1 as ID from NewYear where ID<2208--以2208樓 ),NewYear168 as (select *,(ID-889)/88 as ID2 from NewYear where (ID-888)/8=(ID-888)*1.0/8 ) select t2.ID as [Floor] ,Qty=case row_Number()over(partition by t.ID2 order by newID()) when 1 then 188 when 2 then 88 when 3 then 68 else 0 end into #NewYear2208 from (select distinct ID2 from NewYear168)t cross apply (select top 8 * from NewYear168 where ID2=t.ID2 order by NewID() )t2 option(MAXRECURSION 0) ;with HappyNewYear as ( select [Floor],NewRow=row_Number()over(order by newID()) from #NewYear2208 where Qty=0 ) ,NewYear2010 as ( select * from #NewYear2208 where Qty>0 union all select [Floor], Qty=case when NewRow<=3 then 168 when NewRow<=6 then 118 when NewRow<=7 then 108 when NewRow<=8 then 38 when NewRow<=9 then 28 else ((abs(checksum(newID()))-1)-1)%18+1 end from HappyNewYear ) select [Floor]as 樓層,cast(stuff([Qty],len([Qty]),1,'8') as int) as 中獎紅包 from NewYear2010 order by 1
![]()
推荐阅读更多>
- 今天下午微软大会哦,该怎么处理
- SQL SA用户名无法登陆!创建的用户名也无法登陆,该怎么解决
- 新建一字段,使它的值是原字段A和B的相加值解决思路
- 3表以上的站内搜索解决方法
- 请sql server DBA 看过来!解决办法
- 用SQL语句怎么在一次插入多条数据上实现自增语句
- 安装sql 2008,提示要删除SQL Server 2005 Express 工具解决思路
- SQL SERVER 根据时间查询有关问题,超难,求解
- 【阿段烂诗一首《论SQL版》】解决方法
- 主从结构的分区表是否应该使用相同的分区方案解决思路
- SQL当中的多个排序有关问题
- sqlserver 默认值,该怎么解决
- sql语句,Orz解决思路
- sp_addextendedproperty 插入描述的有关问题,非常急
- 如何将char转换成MONEY帮帮小弟
- 数据库 sql2008 数据偏移(824异常)
- 创设或更改SQL Server数据库失败
- asp施用ADO连接 sql server 2005出错
- 请问,关于还原数据库的有关问题
- 求个sql查询话语