日期:2014-05-18  浏览次数:20505 次

请详细解释 下面的 sql 语句
select count(*) as iterance_count from(SELECT DBVIEW_artru_ZD.ARTRUID, DBVIEW_artru_ZD.CompanyCode, DBVIEW_artru_ZD.PublishDate, DBVIEW_artru_ZD.ARTRUStyle, DBVIEW_artru_ZD.ARTRUItem, DBVIEW_artru_ZD.Currency, DBVIEW_artru_ZD.ARTRU1, DBVIEW_artru_ZD.ARTRU2, DBVIEW_artru_ZD.ARTRU3, DBVIEW_artru_ZD.ARTRU4, DBVIEW_artru_ZD.ARTRU5, DBVIEW_artru_ZD.ARTRU6, DBVIEW_artru_ZD.ARTRU7, DBVIEW_artru_ZD.ARTRU8, DBVIEW_artru_ZD.ARTRU9, DBVIEW_artru_ZD.ARTRU10, DBVIEW_artru_ZD.ARTRU11, DBVIEW_artru_ZD.ARTRU12, DBVIEW_artru_ZD.ARTRU13, DBVIEW_artru_ZD.ARTRU14, DBVIEW_artru_ZD.ARTRU15, DBVIEW_artru_ZD.ARTRU16, DBVIEW_artru_ZD.ARTRU17, DBVIEW_artru_ZD.ARTRU18, DBVIEW_artru_ZD.ARTRU19, DBVIEW_artru_ZD.ARTRU20, DBVIEW_artru_ZD.ARTRU21, DBVIEW_artru_ZD.ARTRU22, DBVIEW_artru_ZD.ARTRU23, DBVIEW_artru_ZD.ARTRU24, DBVIEW_artru_ZD.ARTRU25, DBVIEW_artru_ZD.ARTRU26, DBVIEW_artru_ZD.ARTRU27, DBVIEW_artru_ZD.ARTRU28, DBVIEW_artru_ZD.ARTRU29, DBVIEW_artru_ZD.ARTRU30, DBVIEW_artru_ZD.ARTRU31,DBVIEW_artru_ZD.GUID AS _GUID_DBVIEW_artru_ZD FROM DBVIEW_artru_ZD DBVIEW_artru_ZD )YM group by ARTRUID having count(*)>1

------解决方案--------------------
SQL code
select count(*) as iterance_count from
(
    SELECT 
        DBVIEW_artru_ZD.ARTRUID, DBVIEW_artru_ZD.CompanyCode, DBVIEW_artru_ZD.PublishDate, DBVIEW_artru_ZD.ARTRUStyle, 
        DBVIEW_artru_ZD.ARTRUItem, DBVIEW_artru_ZD.Currency, DBVIEW_artru_ZD.ARTRU1, DBVIEW_artru_ZD.ARTRU2, DBVIEW_artru_ZD.ARTRU3, 
        DBVIEW_artru_ZD.ARTRU4, DBVIEW_artru_ZD.ARTRU5, DBVIEW_artru_ZD.ARTRU6, DBVIEW_artru_ZD.ARTRU7, DBVIEW_artru_ZD.ARTRU8, 
        DBVIEW_artru_ZD.ARTRU9, DBVIEW_artru_ZD.ARTRU10, DBVIEW_artru_ZD.ARTRU11, DBVIEW_artru_ZD.ARTRU12, 
        DBVIEW_artru_ZD.ARTRU13, DBVIEW_artru_ZD.ARTRU14, DBVIEW_artru_ZD.ARTRU15, DBVIEW_artru_ZD.ARTRU16, 
        DBVIEW_artru_ZD.ARTRU17, DBVIEW_artru_ZD.ARTRU18, DBVIEW_artru_ZD.ARTRU19, DBVIEW_artru_ZD.ARTRU20, 
        DBVIEW_artru_ZD.ARTRU21, DBVIEW_artru_ZD.ARTRU22, DBVIEW_artru_ZD.ARTRU23, DBVIEW_artru_ZD.ARTRU24, 
        DBVIEW_artru_ZD.ARTRU25, DBVIEW_artru_ZD.ARTRU26, DBVIEW_artru_ZD.ARTRU27, DBVIEW_artru_ZD.ARTRU28, 
        DBVIEW_artru_ZD.ARTRU29, DBVIEW_artru_ZD.ARTRU30, DBVIEW_artru_ZD.ARTRU31,DBVIEW_artru_ZD.GUID AS _GUID_DBVIEW_artru_ZD 
    FROM DBVIEW_artru_ZD DBVIEW_artru_ZD 
)YM --独立子查询,从这个表中
group by ARTRUID having count(*)>1 --根据ARTRUID分组,取出分组后count(1)> 1 的集合

------解决方案--------------------
SQL code
--一个统计查询语句,统计记录数:
select count(*) as iterance_count from(
--从一个子查询来统计
SELECT DBVIEW_artru_ZD.ARTRUID, DBVIEW_artru_ZD.CompanyCode, DBVIEW_artru_ZD.PublishDate, DBVIEW_artru_ZD.ARTRUStyle, 
DBVIEW_artru_ZD.ARTRUItem, DBVIEW_artru_ZD.Currency, DBVIEW_artru_ZD.ARTRU1, DBVIEW_artru_ZD.ARTRU2, DBVIEW_artru_ZD.ARTRU3, 
DBVIEW_artru_ZD.ARTRU4, DBVIEW_artru_ZD.ARTRU5, DBVIEW_artru_ZD.ARTRU6, DBVIEW_artru_ZD.ARTRU7, DBVIEW_artru_ZD.ARTRU8, 
DBVIEW_artru_ZD.ARTRU9, DBVIEW_artru_ZD.ARTRU10, DBVIEW_artru_ZD.ARTRU11, DBVIEW_artru_ZD.ARTRU12, DBVIEW_artru_ZD.ARTRU13, 
DBVIEW_artru_ZD.ARTRU14, DBVIEW_artru_ZD.ARTRU15, DBVIEW_artru_ZD.ARTRU16, DBVIEW_artru_ZD.ARTRU17, DBVIEW_artru_ZD.ARTRU18, 
DBVIEW_artru_ZD.ARTRU19, DBVIEW_artru_ZD.ARTRU20, DBVIEW_artru_ZD.ARTRU21, DBVIEW_artru_ZD.ARTRU22, DBVIEW_artru_ZD.ARTRU23, 
DBVIEW_artru_ZD.ARTRU24, DBVIEW_artru_ZD.ARTRU25, DBVIEW_artru_ZD.ARTRU26, DBVIEW_artru_ZD.ARTRU27, DBVIEW_artru_ZD.ARTRU28, 
DBVIEW_artru_ZD.ARTRU29, DBVIEW_artru_ZD.ARTRU30, DBVIEW_artru_ZD.ARTRU31,DBVIEW_artru_ZD.GUID AS _GUID_DBVIEW_artru_ZD 
FROM DBVIEW_artru_ZD DBVIEW_artru_ZD 
--上面一个子查询,用了一大堆另外,其实,由于只是从一个表中查的,完全可以把除 from 后面的那个 DBVIEW_artru_ZD 保留外,
--其他DBVIEW_artru_ZD及其后面的.号全去除.即,它等价于:
/*
SELECT ARTRUID, CompanyCode, PublishDate, ARTRUStyle, 
ARTRUItem, Currency, ARTRU1, ARTRU2, ARTRU3, 
ARTRU4, ARTRU5, ARTRU6, ARTRU7, ARTRU8, 
ARTRU9, ARTRU10, ARTRU11, ARTRU12, ARTRU13, 
ARTRU14, ARTRU15, ARTRU16,