日期:2014-05-18  浏览次数:20461 次

急等 sql函数修改问题
SQL code

set ANSI_NULLS ON
set QUOTED_IDENTIFIER ON
go

 ALTER FUNCTION [dbo].[fnGetDistance]

 --LatBegin 开始经度
 --LngBegin 开始维度
(@LatBegin REAL, @LngBegin REAL, @LatEnd REAL, @LngEnd REAL) 

       RETURNS FLOAT

       AS

BEGIN

       --距离(千米)

       DECLARE @Distance      REAL

       DECLARE @EARTH_RADIUS  REAL

       SET @EARTH_RADIUS = 6378.137 
      
       

       DECLARE @RadLatBegin  REAL,

               @RadLatEnd    REAL,

               @RadLatDiff   REAL,

               @RadLngDiff   REAL

       

       SET @RadLatBegin = @LatBegin *PI()/ 180.0 

       SET @RadLatEnd = @LatEnd *PI()/ 180.0 

       SET @RadLatDiff = @RadLatBegin - @RadLatEnd 

       SET @RadLngDiff = @LngBegin *PI()/ 180.0 - @LngEnd *PI()/ 180.0 

       

       SET @Distance = 2 *ASIN(

               SQRT(

                   POWER(SIN(@RadLatDiff / 2), 2)+COS(@RadLatBegin)*COS(@RadLatEnd) 

                   *POWER(SIN(@RadLngDiff / 2), 2)

               )

           )

       

       SET @Distance = @Distance * @EARTH_RADIUS 

       --SET @Distance = Round(@Distance * 10000) / 10000 

       

       RETURN @Distance

END



要怎么修改才能Select dbo.fnGetDistance
('119.959416','30.273575',(select hotel_mapx from hotelinfo),(select hotel_mapx from hotelinfo))

------解决方案--------------------
declare @a type
select @a=(select top 1 hotel_mapx from hotelinfo)

Select dbo.fnGetDistance('119.959416','30.273575',@a,@a)