日期:2014-05-18  浏览次数:20371 次

搜索表中4到10的6条资料Sql语法
表名: StockDay
欄位:StockID: 股票代號nvarchar(6)
  GroupID: 群組代號 nvarchar(3)
  Dates: 交易日期nvarchar(8)
  Vol: 成交量 int


查詢出StockDay中代號為’1101’的股票,按照日期從大到小排序後的,第4至10的6條資料資料。

Select StockID From StockDay where Select StockID from StockDay where StockID = ‘1101’ Order by Dates 


上面的写的有很大的问题. 数据库烂啊 那个大大帮帮忙啊...

------解决方案--------------------
SQL code

取n到m行

1. 
select top (n-m+1) * from tablename where id not in (select top n id from tablename order by id asc/*|desc*/) 

2. 
select top m * into 临时表(或表变量) from tablename order by columnname -- 将top m笔插入到临时表 
set rowcount n   --只取n条结果
select * from 表变量 order by columnname desc 

3. 
select top n * from  
(select top m * from tablename order by columnname) a 
order by columnname desc 


4.如果tablename里没有其他identity列,那么: 
先生成一个序列,存储在一临时表中.
select identity(int) id0,* into #temp from tablename 

取n到m条的语句为: 
select * from #temp where id0 > =n and id0  <= m 

如果你在执行select identity(int) id0,* into #temp from tablename这条语句的时候报错,那是因为你的DB中间的select into/bulkcopy属性没有打开要先执行: 
exec sp_dboption 你的DB名字,'select into/bulkcopy',true 


5.如果表里有identity属性,那么简单: 
select * from tablename where identity_col between n and m  

6.SQL2005开始.可以使用row_number() over()生成行号
;with cte as
(
 select id0=row_number() over(order by id),* from tablename
)
select * from cte where id0 between n to m