日期:2014-05-18  浏览次数:20488 次

一个表中检查将要写入的记录是否与原有记录重复共三个字段
Field1 Field2 Field3
1 2 3
4 5 6

上面的字段值是有效记录,但现在要进行判断有如下记录,
Field1 Field2 Field3
7 1 8

像这上面的记录就不是有效记录,怎么判断这个值是不是跟原有的记录重复呢?这三个字段都需要逐个进行比较,请大家给个思路。谢谢。

------解决方案--------------------
select * from t_a where 
Field1 not in 
(select Field1 from t_a
union 
select Field2 from t_a
union 
select Field3 from t_a
)
and 
Field2 not in 
(select Field1 from t_a
union 
select Field2 from t_a
union 
select Field3 from t_a
)
and
Field3 not in 
(select Field1 from t_a
union 
select Field2 from t_a
union 
select Field3 from t_a
)
------解决方案--------------------
SQL code

IF EXISTS (SELECT 1 FROM SYSOBJECTS WHERE name = 'tba')
BEGIN
    DROP TABLE tba
END
GO
CREATE TABLE tba
(
    Field1 INT,
    Field2 INT,
    Field3 INT
)
GO
INSERT INTO tba
SELECT 1, 2, 3 UNION
SELECT 4, 5, 6 
GO

SELECT * FROM tba
WHERE    (CHARINDEX(',' + RTRIM(7) + ',',',' + RTRIM(Field1) + ',' + RTRIM(Field2) + ',' + RTRIM(Field3) + ',') + 
        CHARINDEX(',' + RTRIM(1) + ',',',' + RTRIM(Field1) + ',' + RTRIM(Field2) + ',' + RTRIM(Field3) + ',') + 
        CHARINDEX(',' + RTRIM(8) + ',',',' + RTRIM(Field1) + ',' + RTRIM(Field2) + ',' + RTRIM(Field3) + ',')) > 0

------解决方案--------------------
SQL code
----------------------------
-- Author  :fredrickhu(小F,向高手学习)
-- Date    :2012-07-18 13:15:36
-- Version:
--      Microsoft SQL Server 2008 R2 (RTM) - 10.50.1617.0 (Intel X86) 
--    Apr 22 2011 11:57:00 
--    Copyright (c) Microsoft Corporation
--    Enterprise Edition on Windows NT 6.1 <X64> (Build 7600: ) (WOW64)
--
----------------------------
--> 测试数据:[tb]
if object_id('[tb]') is not null drop table [tb]
go 
create table [tb]([Field1] int,[Field2] int,[Field3] int)
insert [tb]
select 1,2,3 union all
select 4,5,6
--------------开始查询--------------------------
declare @Field1 int,@Field2 int ,@Field3 int 
set @Field1=7
set @Field2=1
set @Field3=8
select * from tb where checksum(@field1,@field2,@Field3) in (select checksum(field1,field2,Field3) from tb)
----------------结果----------------------------
/* Field1      Field2      Field3
----------- ----------- -----------

(0 行受影响)
*/

------解决方案--------------------
insert into tb(Field1,Field2,Field3) 
select @Field1,@Field2,@Field3 
where not exists (select null from tb where 
Field1 = @Field1 and Field2 =@Field2 and Field3 = @Field3) 

不知道和4楼的比较起来哪个效率会高点。