日期:2014-05-17  浏览次数:20373 次

sql查询不连续数据分组统计
SQL code
create   table   t(stationno int,laneno int,invoiceid   int,vehcount   int) 
insert   into   t   select   1,10,1   ,100
insert   into   t   select   1,10,2   ,100
insert   into   t   select   1,10,3   ,100
insert   into   t   select   1,10,4   ,100
insert   into   t   select   1,10,5   ,100
insert   into   t   select   1,10,10   ,100
insert   into   t   select   1,10,11   ,100
insert   into   t   select   1,10,12   ,100
insert   into   t   select   1,10,13   ,100
insert   into   t   select   1,10,14   ,100
insert   into   t   select   1,11,1   ,100
insert   into   t   select   1,11,2   ,100
insert   into   t   select   1,11,3   ,100
insert   into   t   select   1,11,4   ,100
insert   into   t   select   1,11,5   ,100
insert   into   t   select   1,11,10   ,100
insert   into   t   select   1,11,11   ,100
insert   into   t   select   1,11,12   ,100
insert   into   t   select   1,11,13   ,100
insert   into   t   select   1,11,14   ,100
insert   into   t   select   2,13,1   ,100
insert   into   t   select   2,13,2   ,100
insert   into   t   select   2,13,3   ,100
insert   into   t   select   2,13,4   ,100
insert   into   t   select   2,13,5   ,100
insert   into   t   select   2,13,10   ,100
insert   into   t   select   2,13,11   ,100
insert   into   t   select   2,13,12   ,100
insert   into   t   select   2,13,13   ,100
insert   into   t   select   2,13,14   ,100
insert   into   t   select   2,12,1   ,100
insert   into   t   select   2,12,2   ,100
insert   into   t   select   2,12,3   ,100
insert   into   t   select   2,12,4   ,100
insert   into   t   select   2,12,5   ,100
insert   into   t   select   2,12,10   ,100
insert   into   t   select   2,12,11   ,100
insert   into   t   select   2,12,12   ,100
insert   into   t   select   2,12,13   ,100
insert   into   t   select   2,12,14   ,100


需要查询到的结果是:
XML code
stationno    laneno    号段    sumvehcount
1    10    1~5    500
1    10    10~14    500
1    11    1~5    500
1    11    10~14    500
2    13    1~5    500
2    13    10~14    500
2    12    1~5    500
2    12    10~14    500




------解决方案--------------------
SQL code
SELECT stationno ,laneno ,cast(MIN(invoiceid) as varchar(10)) 
        + '~'+ cast(MAX(invoiceid) as varchar(10)) AS 号段,sum(vehcount) sumvehcount
FROM (SELECT stationno ,laneno ,invoiceid,vehcount, 
                    invoiceid - ROW_NUMBER() OVER(partition by stationno ,laneno ORDER BY invoiceid) AS grp
            FROM dbo.T ) AS D
GROUP BY stationno ,laneno,grp
/*
stationno   laneno      号段                    sumvehcount
----------- ----------- --------------------- -----------
1           10          1~5                   500
1           10          10~14                 500
1           11          1~5                   500
1           11          10~14                 500
2           12          1~5                   500
2           12          10~14                 500
2           13          1~5                   500
2           13          10~14                 500

(8 行受影响)

*/