日期:2014-05-16  浏览次数:20532 次

JavaScript延时执行function
1.当用户输入搜索条件,即打字的时候起开始计时,到停止输入结束,1秒后执行查询function
2.如果1秒内再有输入动作,再重新计时

JavaScript如何实现?

------解决方案--------------------
试试这个

HTML code

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=gb2312" />
<title>无标题文档</title>
</head>
<script language="javascript">
    function searchKeyWord(id) {
        this.element = document.getElementById(id);
        this.timeID = null;
        this.init();
    }
    searchKeyWord.prototype = {
        init: function() {
            var _self = this;
            this.element.onkeyup = function() {_self.start()};
            this.element.onblur = function() {_self.end()};
        },
        start: function() {
            this.resetTime();
            var _self = this;
            this.timeID = setTimeout(function(){_self.end()}, 1000);
        },
        end: function() {
            if(this.timeID) {
                this.resetTime();
                this.searchIt();
            }
        },
        resetTime: function() {
            clearTimeout(this.timeID);
            this.timeID = null;    
        },
        searchIt: function() {
            var _value = this.element.value.replace(/(^\s*)|(\s*$)/g, '');
            document.getElementById('t').value = _value;
        }
    }
</script>
<body>
<input type="text" id='keyWord' />
<input type="text" id='t' />
<script language="javascript">
    new searchKeyWord('keyWord');
</script>
</body>
</html>

------解决方案--------------------
JScript code
<script type="text/javascript">
var s="";
var index = 0;
var i = 0;
document.onkeypress =function(){
    
    setTimeout("setVal()",1000);
    i++;
    
}

function setVal(){
    index ++;
    if(index==i) {
    s = document.getElementById("txt1").value;
    alert(s);    
    index = 0;
    i=0;
}
        
    
    
}
</script>
<input type=text id="txt1">