日期:2014-05-16  浏览次数:20341 次

一个验证身份证号是否有效的js小例子
看到一个检验身份证号的小例子,觉得不错。
<html>
	<head>
		<title>身份证号是否有效验证</title>
	</head>
	<body>
		请输入身份证号码:<input type="text" size="20" id="asidinput" />
		<input type="button" value="验证" onclick="alert(cidInfo(asidinput.value))" />
		<script>
			var aCity={11:"北京",12:"天津",13:"河北",14:"山西",15:"内蒙古",21:"辽宁",22:"吉林",23:"黑龙江",31:"上海",32:"江苏",33:"浙江",34:"安徽",35:"福建",36:"江西",37:"山东",41:"河南",42:"湖北",43:"湖南",44:"广东",45:"广西",46:"海南",50:"重庆",51:"四川",52:"贵州",53:"云南",54:"西藏",61:"陕西",62:"甘肃",63:"青海",64:"宁夏",65:"新疆",71:"台湾",81:"香港",82:"澳门",91:"国外"} 
			function cidInfo(sId){
			var iSum=0;
			var info="";
			if(!/^\d{17}(\d|x)$/i.test(sId))return false;
			sId=sId.replace(/x$/i,"a");
			if(aCity[parseInt(sId.substr(0,2))]==null)return "Error:非法地区";
			sBirthday=sId.substr(6,4)+"-"+Number(sId.substr(10,2))+"-"+Number(sId.substr(12,2));
			var d=new Date(sBirthday.replace(/-/g,"/"))
			if(sBirthday!=(d.getFullYear()+"-"+ (d.getMonth()+1) + "-" + d.getDate()))return "Error:非法生日";
			for(var i = 17;i>=0;i --) iSum += (Math.pow(2,i) % 11) * parseInt(sId.charAt(17 - i),11);
			if(iSum%11!=1)return "Error:非法证号";
			return aCity[parseInt(sId.substr(0,2))]+","+sBirthday+","+(sId.substr(16,1)%2?"男":"女")
			}
		</script>
	</body>
</html>