public static void main(String args[])
    {
        printNum(1);
    }
    
    public static void printNum(int n)
    {
        if(n == 100)
        {
            System.out.println(n);
        }
        else
        {
            System.out.println(n);
            printNum(n + 1);
        }
    }

------解决方案--------------------
Java code
public class Test1 {
    public static synchronized void main(String[] a) {
        int i =0;
             getNumber(i);
    

    }
    static  void getNumber(int i)
    {          i++;
    System.out.println(i);
        if (i < 100) getNumber(i);
    }
}

------解决方案--------------------
Java code

public class Test
{
   public void Test_1(int a)
   {
       if(a <= 100)
       {
       System.out.println(a);
       Test(++a);
       }
          
       
   }
   
   public static void main(String[] args)
   {
       Test test = new Test();
       test.Test_1(1);
   }
   
}

------解决方案--------------------
code=Java]
public void printNum(int n)
	{
		if(n==1)
			System.out.println(n);
		else
		{
			printNum(n-1);
			System.out.println(n);
		}
	}[
[/code]

------解决方案--------------------
用递归
Java code


printNum(100);

public void printNum(int i){
System.out.println(i);
if(i==1){
 return;
}else{
printNum(--i);
}
}

------解决方案--------------------
Java code
import java.util.Date;
import java.util.Timer;
import java.util.TimerTask;

public class Test01 {

    public static void main(String[] args) {
        final int len = 100;
        final Timer timer = new Timer();
        timer.schedule(new TimerTask() {
            private int i = 1;
            public void run() {
                System.out.println(i++);
                if (i > len) {
                    this.cancel();
                    timer.cancel();
                }
            }
        }, new Date(), 1);
    }
}

------解决方案--------------------
整理了一下2个方法
Java code
import java.util.Timer;
import java.util.TimerTask;

public class T {
  public static void main(String[] arge) {
    show(100);
    show2(100);
  }

  public static void show(int num) {
    if (num > 1) {
      show(num - 1);
    }
    System.out.println(num);
  }

  public static void show2(final int num) {
    final Timer timer = new Timer();
    timer.schedule(new TimerTask() {
      private int i = 0;

      @Override
      public void run() {
        if (i <= num) {
          System.out.println(i++);
        } else {
          timer.cancel();
        }
      }
    }, 0, 1);
  }
}

------解决方案--------------------
探讨

Java code
    public static void main(String args[])
    {
        printNum(1);
    }
    
    public static void printNum(int n)
    {
        if(n == 100)
        {
            System.out.println(n);