jsp getParameter 不能获得返回值问题(急)
我通过前一个页面提交到后一个页面，然后就报错，到底怎么回事啊！在线等～  
type   Exception   report  

message  

description   The   server   encountered   an   internal   error   ()   that   prevented   it   from   fulfilling   this   request.  

exception  

org.apache.jasper.JasperException  
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:372)  
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:292)  
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:236)  
javax.servlet.http.HttpServlet.service(HttpServlet.java:802)  


root   cause  

java.lang.NullPointerException  
org.apache.jsp.login_jsp._jspService(login_jsp.java:88)  
org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:94)  
javax.servlet.http.HttpServlet.service(HttpServlet.java:802)  
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:324)  
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:292)  
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:236)  
javax.servlet.http.HttpServlet.service(HttpServlet.java:802)  


note   The   full   stack   trace   of   the   root   cause   is   available   in   the   Apache   Tomcat/5.0.28   logs.  


------解决方案--------------------
tomcat/work下 login_jsp.java:88行是什么？

String aaa=(String)request.getParameter( "name ");
------解决方案--------------------
把代码贴出来看看!
我的异常网推荐解决方案：The server encountered an internal error () that prevented it from fulfilling this request.,http://www.aiyiweb.com/java-web/317.html