日期:2014-05-18 浏览次数:21065 次
static string GetRepeatedElement(string[] strs, int repeats)
{
Dictionary<string, int> dict = new Dictionary<string, int>();
foreach (string s in strs)
{
if (dict.ContainsKey(s)) dict[s]++;
else dict[s] = 1;
}
foreach (string s in dict.Keys)
{
if (dict[s] == repeats) return s;
}
return null;
}
------解决方案--------------------
private string[] bindGrid(string[] array,int i)
{
HashTable ht = new HashTable();
foreach(string s in array)
{
if(ht.ContainsKey(s))
ht[s]=Convert.ToInt32(ht[s])+1;
else
ht.Add(s,1);
}
List<string> list=new List<string>();
IDictionaryEnumerator ide = ht.GetEnumerator();
while(ide.MoveNext())
{
if(ide.Value.ToString()==i)
list.Add(ide.Value.ToString());
}
string[] result= list.ToArray();
return result;
}
------解决方案--------------------
string[] asa = new string[] {"1","1","2","1","3","3","1","5","3","3","3","3","3" };
bindGrid(asa,5);
private static void bindGrid(string[] n,int max)
{
int count=0;
for (int i = 0; i < n.Length;i++ )
{
for (int j = i + 1; j < n.Length;j++ )
{
if (count-1 > max)
{
Console.Write(n[i].ToString());
Console.Read();
}
else
{
if (n[i].Equals(n[j])) count++;
}
}
}
}
------解决方案--------------------
string[] str = new string[] { "a", "b", "a", "c", "d", "e", "c", "a" ,"e","a","c","c","c","a"};
public System .Collections .ArrayList bindGrid(string[] str, int i)
{
int counter=0;
System.Collections.ArrayList alist = new System.Collections.ArrayList();
for (int j = 0; j < str.Length; j++)
{
counter = 0;
for (int k = 0; k < str.Length; k++)
{
if (str[j] == str[k])
counter++;
}
if (counter == i&& alist .IndexOf (str [j])<0)//滤除相同元素
alist.Add(str[j]);
}
return alist;
}
------解决方案--------------------
返回string[] 的话可参考5楼的方式.
return (string [])alist.ToArray(typeof(string));
------解决方案--------------------