日期:2014-05-18  浏览次数:20768 次

如何让程序能够开机自动运行??
这个是应该写注册表么??

就30分了,还望不吝赐教啊!!

------解决方案--------------------
C# code
//此方法把启动项加载到注册表中

//获得应用程序路径
string strAssName = Application.StartupPath + @"\" + Application.ProductName + @".exe";
//获得应用程序名
string ShortFileName = Application.ProductName;

RegistryKey rgkRun = Registry.LocalMachine.OpenSubKey("SOFTWARE\\Microsoft\\Windows\\CurrentVersion\\Run", true);
if (rgkRun == null)
{
    rgkRun = Registry.LocalMachine.CreateSubKey("SOFTWARE\\Microsoft\\Windows\\CurrentVersion\\Run");
}
rgkRun.SetValue(ShortFileName, strAssName);


//此删除注册表中启动项

//获得应用程序名
string ShortFileName = Application.ProductName;

RegistryKey rgkRun = Registry.LocalMachine.OpenSubKey("SOFTWARE\\Microsoft\\Windows\\CurrentVersion\\Run", true);
if (rgkRun == null)
{
    rgkRun = Registry.LocalMachine.CreateSubKey("SOFTWARE\\Microsoft\\Windows\\CurrentVersion\\Run");
}
rgkRun.DeleteValue(ShortFileName, false);

------解决方案--------------------
探讨
C# code
//此方法把启动项加载到注册表中

//获得应用程序路径
string strAssName = Application.StartupPath + @"\" + Application.ProductName + @".exe";
//获得应用程序名
string ShortFileName = Application.ProductName;

Registry……

------解决方案--------------------
探讨
C# code
//此方法把启动项加载到注册表中

//获得应用程序路径
string strAssName = Application.StartupPath + @"\" + Application.ProductName + @".exe";
//获得应用程序名
string ShortFileName = Application.ProductName;

Registry……