/// <summary>
/// 小数位数计算
/// </summary>
/// <param name="je">数值</param>
/// <param name="xsw">小数位</param>
/// <param name="jefs">0.四舍五入1.进1法 2.舍1法 3.下取整四舍六入五成双</param>
/// <remarks></remarks>
public static double f_round(double je, int xsw, int jefs)
{
    switch (jefs) {
        case 0:
            //四舍五入
            return Math.Round(je, xsw, MidpointRounding.AwayFromZero);
        case 1:
            //进1(上取整)
            string str = "1";
            for (int i = 1; i <= xsw; i++) {
                str += "0";
            }

            int temp1 = Convert.ToInt32(str);
            return Math.Floor(je * temp1) / temp1;
        case 2:
            //舍1(下取整)
            break;

        case 3:
            //四舍六入五成双
            break;

    }

}

------解决方案--------------------
那就试试这个:
decimal d = 10.45446m;
Math.Ceiling(d * 100) / 100

OR  

Math.Round(d + 0.005)

------解决方案--------------------
http://msdn.microsoft.com/zh-cn/library/system.math.round(VS.80).aspx

double d = Math.Round(10.45446, 2, MidpointRounding.AwayFromZero);