日期:2014-05-17 浏览次数:20486 次
string ss = "abcdefg";
Stack<char> stack = new Stack<char>();
foreach (char c in ss)
{
stack.Push(c);
}
ss = "";
foreach (char c in stack)
{
ss += c.ToString();
}
MessageBox.Show(ss):
或者
string ss = "abcdefg";
string des = "";
for(int i=ss.Length-1;i>=0;i--)
{
des += ss[i].ToString();
}
MessageBox.Show(des);
------解决方案--------------------
入栈出栈即可
------解决方案--------------------
string oldStr = "abcd as,ccd.dsa";
string cutStr = " ,.";
string tempStr = "";
string re = "";
for (int i = oldStr .Length - 1; i >= 0 ;i-- )
{
char c = oldStr [i];
bool iscut = false;
foreach (char cut in cutStr)
{
if(cut == c){iscut = true;continue;}
}
if(iscut){re = tempStr + c + re;tempStr = "";}
else{tempStr = c + tempStr;}
}
return tempStr + re;
------解决方案--------------------
电话面试,别人主要看你的反应能力和解决问题的思路,面试者自己都不一定能写出来都是网上找的鬼题目。
------解决方案--------------------
希望这个可以帮到你:
private void Form1_Load(object sender, EventArgs e)
{
string[] aa = { "wo","ai","kan","mao","pian"};
string temp = "";
for (int i = 0; i < aa.Length / 2;i++)
{
temp = aa[aa.Length - i - 1];
aa[aa.Length - i - 1] = aa[i];
aa[i] = temp;
}
for (int j = 0; j < aa.Length; j++)
{
MessageBox.Show(aa[j]);
}
//依次弹出:pian,mao,kan,ai,wo
}
------解决方案--------------------
class stack:IStack
{
stack s;
stack next;
private string data;
public string Data
{
get { return data; }
set { data = value; }
}
public static int len = 0;
public void push(string data)
{
next = new stack();
next.data = data;
len++;
if (len > 0)
next.next = s;
else
{
s = new stack();
s.data = data;
}
s = next;
}
public string pop()
{
string str = s.data;
if(s.next!=null)
s = s.next;