日期:2014-05-18 浏览次数:20616 次
create table tb(docid int,doctitle nvarchar(10))
insert into tb select 1,'hello'
insert into tb select 2,'nihao'
insert into tb select 3,'你好'
insert into tb select 120,'你好aaaa'
declare @str varchar(2000)='1,3,3,120,2,1'
set @str='select a.* from tb a,(select '+REPLACE(@str,',',' as id union all select ')
+') b where a.docid=b.id'
print @str
exec (@str)
/*
docid doctitle
----------- ----------
1 hello
3 你好
3 你好
120 你好aaaa
2 nihao
1 hello
------解决方案--------------------
use tempdb
go
--测试数据
declare @s varchar(1000)
set @s='ak47,mp5,1,23'
/*要求输出结果
S
----
ak47
mp5
1
23
*/
--3种方法对比:
--1.[朴实]动态Exec方法:
declare @s1 varchar(1000)
set @s1=right(replace(','+@s,',',''' as S union select '''),len(replace(','+@s,',',''' as S union select '''))-12)+''''
exec(@s1)
--2.[变通]表交叉方法:
select replace(reverse((left(s,charindex(',',s)))),',','') as S from(
select r,reverse(left(@s,r))+',' as s
from(
select (select count(*) from sysobjects where name<=t.name ) as r
from sysobjects t
)a where r<=len(@s)
and left(@s+',',r+1) like '%,'
)t order by r
--3.[高级]XML方法:
DECLARE @idoc int;
DECLARE @doc xml;
set @doc=cast('<Root><item><S>'+replace(@s,',','</S></item><item><S>')+'</S></item></Root>' as xml)
EXEC sp_xml_preparedocument @Idoc OUTPUT, @doc
SELECT * FROM OPENXML (@Idoc, '/Root/item',2)
WITH (
[S] varchar(10)
)