--分拆列值
--原著：邹建
--改编：爱新觉罗.毓华(十八年风雨,守得冰山雪莲花开)  2007-12-16  广东深圳

/*
有表tb, 如下: 
id          value 
----------- ----------- 
1          aa,bb 
2          aaa,bbb,ccc 
*/
--欲按id,分拆value列, 分拆后结果如下: 
/*
id          value 
----------- -------- 
1          aa 
1          bb 
2          aaa 
2          bbb 
2          ccc 
*/
--1. 旧的解决方法(sql server 2000) 
select top 8000 id = identity(int, 1, 1) into # from syscolumns a, syscolumns b 

select A.id, substring(A.[values], B.id, charindex(',', A.[values] + ',', B.id) - B.id) 
from tb A, # B 
where substring(',' + A.[values], B.id, 1) = ',' 

drop table # 

--2. 新的解决方法(sql server 2005) 

create table tb(id int,value varchar(30)) 
insert into tb values(1,'aa,bb') 
insert into tb values(2,'aaa,bbb,ccc') 
go 
select A.id, B.value 
from( 
    select id, [value] = convert(xml,' <root> <v>' + replace([value], ',', ' </v> <v>') + ' </v> </root>') from tb 
)A 
outer apply( 
    select value = N.v.value('.', 'varchar(100)') from A.[value].nodes('/root/v') N(v) 
)B 

drop table tb 

/* 
id          value 
----------- ------------------------------ 
1          aa 
1          bb 
2          aaa 
2          bbb 
2          ccc 

(5 行受影响) 
*/

------解决方案--------------------
SQL code

create table mac
(id int, member varchar(60))

insert into mac
select 1, 'jacky;mandy;amy' union all
select 2, '' union all 
select 3, 'wendy;herry'


select a.id,
substring(a.member+';',b.number,charindex(';',a.member+';',b.number)-b.number) 'member'
from mac a
inner join master.dbo.spt_values b
on b.[type]='P' and 
substring(';'+a.member,b.number,1)=';'
where a.member<>''

id          member
----------- ---------
1           jacky
1           mandy
1           amy
3           wendy
3           herry