日期:2014-05-18 浏览次数:20625 次
SELECT a.SceneId, COUNT(distinct a.UsersName) AS Expr1
FROM ApplyInfo AS a INNER JOIN
UsersInfo AS u ON a.UsersName = u.UsersName
WHERE (u.UsersSex = '男')
GROUP BY a.SceneId
SELECT S.SceneName, COUNT(distinct a.UsersName) AS Expr1
FROM ApplyInfo AS a INNER JOIN
UsersInfo AS u ON a.UsersName = u.UsersName
Inner join
SceneInfo AS S on a.SceneId=S.SceneId
WHERE (u.UsersSex = '男')
GROUP BY S.SceneName
------解决方案--------------------
SELECT SC.SceneName, COUNT(distinct a.UsersName) AS Expr1
FROM ApplyInfo AS a INNER JOIN
UsersInfo AS u ON a.UsersName = u.UsersName
inner join sceneinfo SC on SC.sceneid =a.sceneid
WHERE (u.UsersSex = '男')
GROUP BY SC.SceneName