日期:2014-05-18 浏览次数:20685 次
SELECT REPLACE(REPLACE(REPLACE(REPLACE(convert(varchar(50),GETDATE(),121),'-',''),':',''),' ',''),'.','')
------解决方案--------------------
字符串转化到时间格式,先创建个函数,然后调用函数就行了
CREATE FUNCTION ChangeStrToDate(@Str VARCHAR(100))
RETURNS VARCHAR(100)
AS
BEGIN
DECLARE @Date VARCHAR(10)
DECLARE @Time VARCHAR(100)
DECLARE @Month VARCHAR(10)
DECLARE @Min VARCHAR(10)
SET @Date = LEFT(@Str,8)
SET @Time = RIGHT(@Str,9)
SET @Month = SUBSTRING(@Date,5,2)
SET @Date = STUFF(@Date,5,2,'-' + @Month + '-')
SET @Min = SUBSTRING(@Time,3,2)
SET @Time = STUFF(STUFF(@Time,3,2,':' + @Min + ':'),9,0,'.')
RETURN @Date + ' ' + @Time
END
GO
SELECT DBO.ChangeStrToDate('20120418045858977')