日期:2014-05-18 浏览次数:20576 次
if object_id('[wb]') is not null drop table [wb]
go
create table [wb]([ID] varchar(1),[QuestionClassification] varchar(27))
insert [wb]
select 'a','1,2,3,4,5,6,7' union all
select 'b','11,22,33,44,55,66,77' union all
select 'c','111,222,333,444,555,666,777'
go
if object_id('[wu]') is not null drop table [wu]
go
create table [wu]([id] int,[name] varchar(2),[KeyWord] varchar(8))
insert [wu]
select 1,'aa','1,22,333' union all
select 2,'bb','111,1,22' union all
select 3,'cc','22,33'
go
select a.* from wu a
join
(
select substring(QuestionClassification,b.number,charindex(',',QuestionClassification+',',b.number)-b.number) as num
from wb a
join master..spt_values b on b.type='P' and charindex(',',','+QuestionClassification,b.number)=b.number
where ID='a'
) b
on charindex(','+b.num+',',','+a.keyword+',')>0
/**
id name KeyWord
----------- ---- --------
1 aa 1,22,333
2 bb 111,1,22
(2 行受影响)
**/
------解决方案--------------------
/*
create function [dbo].[m_split](@c varchar(2000),@split varchar(2))
returns @t table(col varchar(200))
as
begin
while(charindex(@split,@c) <>0)
begin
insert @t(col) values (substring(@c,1,charindex(@split,@c)-1))
set @c = stuff(@c,1,charindex(@split,@c),'')
end
insert @t(col) values (@c)
return
end
*/
declare @wb table([ID] varchar(1),[QuestionClassification] varchar(27))
insert @wb
select 'a','1,2,3,4,5,6,7' union all
select 'b','11,22,33,44,55,66,77' union all
select 'c','111,222,333,444,555,666,777'
declare @wu table([id] int,[name] varchar(2),[KeyWord] varchar(8))
insert @wu
select 1,'aa','1,22,333' union all
select 2,'bb','111,1,22' union all
select 3,'cc','22,33'
;with maco as
(
select * from [dbo].[m_split]((select [QuestionClassification] from @wb where ID='a'),',')
)
select * from @wu a ,maco b
where charindex(','+ltrim(b.col)+',',','+a.[KeyWord]+',')>0
/*
id name KeyWord col
----------- ---- -------- ------------------------------
1 aa 1,22,333 1
2 bb 111,1,22 1
*/
------解决方案--------------------