日期:2014-05-18 浏览次数:20556 次
SELECT a.*
FROM cardtran a join
(SELECT cardno, balance
FROM cardtran
GROUP BY (cardno, balance)
HAVING COUNT(*) > 1) b on a.cardno = b.cardno and a.balance = b.balance
------解决方案--------------------
select t1.*
from cardtran t1
where exists (
select 1 from cardtran t2
where t1.cardno=t2.cardno and t1.balance=t2.balance
group by t2.cardno,t2.balance
having count(1)>1
)
------解决方案--------------------
其實二樓的改一點就可以了
SELECT a.*
FROM cardtran a join
(SELECT cardno, balance
FROM cardtran
GROUP BY cardno, balance--去掉括號
HAVING COUNT(*) > 1) b on a.cardno = b.cardno and a.balance = b.balance