日期:2014-05-17 浏览次数:20813 次
create proc ccgc
@p_aa), -- 4位
@p_bb varchar(20), -- 20位用
@p_ksrq varchar(8) = '',
@p_jzrq varchar(8) = '',
as
...
insert into #bb exec dbo.up_this @p_aa = @p_aa, -- char(4)
@p_bb = @p_bb, -- varchar(20)
@p_yigerq = @p_ksrq, -- varchar(8)
@p_cc = '', -- char(1)
@p_dd = '', -- varchar(255)
@p_ee = '', -- varchar(255)
@p_ff = '', -- varchar(255)
@p_gg = '', -- varchar(255)
...
declare @begindate datetime set @begindate='2012-08-01'
declare @enddate datetime set @enddate='2012-08-10'
while (@begindate<=@enddate)
begin
--select @begindate
insert into #bb exec dbo.up_this @p_aa = @p_aa, -- char(4)
@p_bb = @p_bb, -- varchar(20)
@p_yigerq = @p_ksrq, -- varchar(8)
@p_cc = '', -- char(1)
@p_dd = '', -- varchar(255)
@p_ee = '', -- varchar(255)
@p_ff = '', -- varchar(255)
@p_gg = '', -- varchar(255)
set @begindate=dateadd(d,1,@begindate)
end
------解决方案--------------------
declare @p_ksrq varchar(10),@p_jzrq varchar(10),@rq varchar(10),@i int
select @p_ksrq='2012-08-01',@p_jzrq='2012-08-15',@i=0
while @i<=datediff(day,@p_ksrq,@p_jzrq)
begin
set @rq=dateadd(day,@i,@p_ksrq)
select @rq --@rq为你需要查询的日期
set @i=@i+1
end
------解决方案--------------------
declare @begin_date varchar(10)
declare @end_date varchar(10)
declare @date varchar(10)
declare @i int
set @begin_date='2012-08-01'
set @end_date='2012-08-15'
set @i=0
while @i<=datediff(day,@begin_date,@end_date)
begin
select @date=dateadd(day,@i,@begin_date)
print @date
set @i=@i+1
end