String[] s = { "1,2,3,4", "1，2，3，4", "1，2,3,4", "1，2,3,4，" };
for (int i = 0; i < s.length; i++) {
    System.out.println(s[i].matches("(\\d[,，])+(\\d[,，]?)?"));
}

------解决方案--------------------
上面的那个有 bug，改进一下：

Java code
public class Test {

    public static void main(String[] args) {
        String[] s = { "1,2,3,4",
                "1，2，3，4", 
                "33", 
                "1，2,3,4",
                "1，2,3,4，",
                "1,3,4,5,6,7，8，9，1000，"
            };
        String pattern = "(?:\\d(?!\\d)[,，]?)+";
        for (int i = 0; i < s.length; i++) {
            System.out.println(s[i] + " " + s[i].matches(pattern));
        }
    }
}

------解决方案--------------------
Java code
str.matches("(\\d+\\W+?)+")

------解决方案--------------------
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Java codestr.matches("(\\d+\\W+?)+")