package com.test;

import java.util.*;

public class MultiSortTest
{
    public static void main(String[] args)
    {
        List<Map<String, String>> list = new ArrayList<Map<String, String>>();
        Map<String, String> map = new HashMap<String, String>();
        map.put("time", "2012-2-1");
        map.put("price", "203");
        map.put("title", "J2EE ebook ");
        list.add(map);
        Map<String, String> map1 = new HashMap<String, String>();
        map1.put("time", "2012-3-1");
        map1.put("price", "103");
        map1.put("title", "think in java ");
        list.add(map1);
        HashMap<String, String>[] maps = new HashMap[list.size()];
        list.toArray(maps);
        System.out.println("sort by time:");
        sort(maps, "time");
        printMaps(maps);
        System.out.println("\nsort by price:");
        sort(maps, "price");
        printMaps(maps);
        System.out.println("\nsort by title:");
        sort(maps, "title");
        printMaps(maps);
        
    }
    public  static void printMaps(HashMap<String, String>[] maps )
    {
        for(HashMap<String, String> map:maps)
        {
            System.out.println(map.get("time")+"\t"+map.get("price")+"\t"+map.get("title"));
        }
    }
    public static void sort(HashMap<String, String>[] maps,final String key)
    {
        Arrays.sort(maps,new Comparator<HashMap<String,String>>(){
            public int compare(HashMap<String, String> o1,
                    HashMap<String, String> o2)
            {
                //利用比较hashcode来排序不太准确，实际应用中要分析的更详细点
                return o1.get(key).hashCode()-o2.get(key).hashCode();
            }
        });
    }
}

------解决方案--------------------
探讨


将list转换成数组，然后利用Arrays对数组的排序功能，当然自己要实现一个Comparator
Java code

package com.test;

import java.util.*;

public class MultiSortTest
{
    public static void main(String[] args)
    {
        List<Map<S……